1. A congressional committee wishes to e

1. A congressional committee wishes to estimate the average annual subsidy received by tenant farmers in asouthern state. A random sample of 495 farms is taken, the sample mean is found to be $7,850 with a samplestandard deviation of $750. Compute the 99% confidence interval estimate of the annual subsidy?2. Business statistics students claim that they spend at least 3 hours studying for and working through statisticspractice problems per week. A random sample of 44 college students enrolled in a business statistics course wasasked how many hours he or she spent practicing working statistics problems. The sample average was found tobe 2.4 hours per week with a standard deviation of 1.25 hours. Using the p-value method and ? = .01, determineif the students are studying the amount of time that was claimed.CLICK HERE FOR MORE INFORMATION ON THIS PAPER? PRICE?..3. You are the manager of a restaurant that delivers pizza to college dormitory rooms. You have just changed yourdelivery process to a method that you think will reduce the mean time, from the order to the completion of thedelivery, down from the current 25 minute delivery time. A sample of 36 orders using the new delivery processyields a sample mean of 22.4 minutes and a standard deviation of 6 minutes. Can you conclude that the newdelivery process has reduced the population mean delivery time? Use the p-value method and a significance levelof 2.5% to answer this question.4. A survey is planned to determine the mean annual family medical expenses of employees of a large company.The management of the company wishes to be 90% confident that the sample mean is correct to within $50 of thepopulation mean annual family medical expenses. A previous study indicates that the standard deviation isapproximately $400. How large of a sample size is needed?5. Two hundred people are randomly chosen at a shopping mall to taste-test a new brand of fruit drink. They areasked to rate the drink on a scale from 1 to 5, with 5 being very good and 1 being very bad. The results of thesurvey reveal that the sample average rating is 3.63 with a standard deviation of 1.22. Compute the 90%confidence interval estimate of the mean drink rating? CLICK HERE FOR MORE INFORMATION ON THIS PAPER? PRICE?..

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